URL details: holdenweb.blogspot.com/2011/11/blogging-mathematics.html

URL title: For Some Value of "Magic": Blogging Mathematics
URL paragraphs: "Any sufficiently advanced technology is indistinguishable from magic" -- Arthur C Clarke Musings from the technological frontier \[P(E) = {n \choose k} p^k (1-p)^{n-k}\] and have it appear as \[P(E) = {n \choose k} p^k (1-p)^{n-k}\] (EDIT: Formula correct
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2022-07-23
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